A rectangular loop of dimension 3 cm by 5 cm is placed perpendicular to a uniform magnetic field of 0.1 T, find the magnetic flux through the loop.
Correct answer: B. 0.15 mWb
- A. 1.5 mWb
- B. 0.15 mWb
- C. 0.015 mWb
- D. 15 mWb
Explanation
The magnetic flux through a surface is given by the formula: Φ = B A cosθ where: Φ = magnetic flux through the surface B = magnitude of the magnetic field A = area of the surface θ = angle between the magnetic field and the surface normal In this case, the rectangular loop is placed perpendicular to the magnetic field, so θ = 0° and cosθ = 1. The area of the loop is A = 3 cm x 5 cm = 15 cm² = 0.0015 m². Substituting the given values into the formula, we get: Φ = (0.1 T) x (0.0015 m²) x cos(0°) = 0.1 x 0.0015 = 0.00015 Wb Converting the result to milliWebers (mWb) by multiplying by 1000, we get: Φ = 0.15 mWb
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About Magnetic Flux
Magnetic flux measures the magnetic field passing through a surface, calculated for a uniform field as Φ = BA cos θ, where θ is the angle between the field and the surface normal. Questions involve area, field strength and orientation, the weber as its unit, and the distinction between flux and magnetic field.
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