A racing car travelling with constant acceleration increases its speed from 10 m/s to 50 m/s over a distance of 60 m. How long does this take?
Correct answer: A. 2.0 s
- A. 2.0 s
- B. 5.0 s
- C. 4.0 s
- D. 8.0 s
Explanation
The scenario describes a uniformly accelerated motion, starting with an initial velocity (u) of 10 m/s and reaching a final velocity (v) of 50 m/s over a distance (s) of 60 m. To find the time taken, we first determine the acceleration using the formula:v2 = u2 + 2as.Rearranging for a, we have: a = (v2 - u2) / (2s) = (502 - 102) / (2 x 60) = 20 m/s2.Next, we use the equation v = u + at to find the time t: t = (v - u) / a = (50 - 10) / 20 = 2 seconds.Therefore, the correct time taken is 2 seconds. Options B, C, and D result from incorrect application of the equations, leading to inaccurate calculations.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Force and Motion
Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
Practise Force and Motion
1,416 free Force and Motion MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Force and Motion questions
In projectile motion the
In straight line motion the
If the initial speed of a projectile is doubled. What will happen to its range?
A particle is moving with a constant speed along straight line path. A force is not required to
Two particles are moving with velocities v1 and v2. Their relative velocity is maximum when the angle between their velocities is:
Horizontal distance travelled by a ball if it's thrown with initial velocity of 20 ms-1 at an angle of 30o is