A proton is projected with a uniform velocity 'v' along the axis of a current carrying solenoid.
Correct answer: D. The proton will continue to move with velocity 'v' along the axis.
- A. The proton will be accelerated along the axis.
- B. The proton path will be circular about the axis.
- C. The proton moves along a helical path.
- D. The proton will continue to move with velocity 'v' along the axis.
Explanation
The proton is traveling in the same direction as the solenoid's axis. Because the magnetic field inside the solenoid is homogenous and parallel to the solenoid, it has no effect on the proton's velocity and it is parallel to the magnetic field( net force on proton is zero) The angle between B and V= 00 According to Lorentz's formula F=q(VxB) or F=qVBsinΘ Here sinΘ =0 this means there will be no force due to the magnetic field at all hence the proton will continue to move with the same velocity along the axis. Since there is no effect on the velocity of the proton so the proton cannot be accelerated along the axis. The proton cannot move in a helical path also.
This question appeared on the KMU Centralized Admission Test 2020 paper, which you can sit online with every answer explained.
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About Charged Particle in a Magnetic Field
A charged particle moving through a magnetic field experiences the Lorentz force, which is perpendicular to both its velocity and the field. The motion may be circular or helical, with questions involving radius, angular frequency, time period, and work done. A stationary charge feels no magnetic force.
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