A proton is projected with a uniform velocity 'v' along the axis of a current carrying solenoid.
Correct answer: D. The proton will continue to move with velocity 'v' along the axis.
- A. The proton will be accelerated along the axis.
- B. The proton path will be circular about the axis.
- C. The proton moves along a helical path.
- D. The proton will continue to move with velocity 'v' along the axis.
Explanation
The proton is traveling in the same direction as the solenoid's axis. Because the magnetic field inside the solenoid is homogenous and parallel to the solenoid, it has no effect on the proton's velocity and it is parallel to the magnetic field( net force on proton is zero) The angle between B and V= 00 According to Lorentz's formula F=q(VxB) or F=qVBsinΘ Here sinΘ =0 this means there will be no force due to the magnetic field at all hence the proton will continue to move with the same velocity along the axis. Since there is no effect on the velocity of the proton so the proton cannot be accelerated along the axis. The proton cannot move in a helical path also.
Last updated
About Charged Particle in a Magnetic Field
A charged particle moving through a magnetic field experiences the Lorentz force, which is perpendicular to both its velocity and the field. The motion may be circular or helical, with questions involving radius, angular frequency, time period, and work done. A stationary charge feels no magnetic force.
Practise Electromagnetism
1,176 free Electromagnetism MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Physics questions like this
Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
A charge is at rest in a magnetic field, then the magnetic force on charge is:
A charge is moving with velocity v, it enters a uniform magnetic field B. The direction of v is perpendicular to B. What is the path of the charge particle inside the magnetic field?
A charge of two microcoulombs (2 μC) moves with velocity of two meter per second (2 m/sec) in the direction of two Tesla magnetic field. The force that will act on it will be:
A charge projected with velocity of 10 m/s in a magnetic field of 10 T at an angle of 60°, if force exerted on charge is 2.78 x 10^-17 N, then value of charge is:
A charged particle entering a uniform magnetic field at right angles to it follows