A projectile is thrown with velocity v at an angle θ with the horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is:
Correct answer: C. vsinθ/√2
- A. vsinθ
- B. 3vsinθ
- C. vsinθ/√2
- D. vsinθ/√3
Explanation
When a projectile is at a height equal to half of the maximum height, the vertical component of the velocity can be determined by considering the relationship between the height and the vertical velocity component. The correct formula to calculate the vertical component of the velocity in this scenario is v_y = v*sin(θ)/√2. This is derived from the fact that at half the maximum height, the vertical component of the velocity is reduced by a factor of √2. Options A, B, and D are incorrect as they do not reflect this relationship accurately.
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About Force and Motion
Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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