A projectile is thrown at an angle of 45° with horizontal, and its range is R1. Another projectile is projected at 45 degrees with vertical and its range is R2. The relation between R1 and R2 is?
Correct answer: C. R1=R2
- A. R2=2R1
- B. R1=2R2
- C. R1=R2
- D. 3R=R1
Explanation
R=Vi2(sin2theta)/g R is same for both θ and (90−θ). If angle w.r.t. vertical is 45° then w.r.t to horizontal it will be 90°-45°= 45°. Hence angle with horizontal and vertical is same so ranges will be same for both angles.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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