A potential of 400 V is applied to a capacitor, the plates of which are 4 mm apart. The strength of electric field is___________?
Correct answer: A. 100 kV/m
- A. 100 kV/m
- B. 10 kV/m
- C. 5 kV/m
- D. 2 kV/m
Explanation
For a uniform electric field between capacitor plates, E = V/d = 400/0.004 = 100,000 V/m. This equals 100 kV/m.
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