A positive point charge is placed at P in front of an earthed metal sheet S. Q & R are two points between P & S as shown in the figure. If the electric field strength at Q & R is respectively EQ & ER and potential at Q & R is respectively VQ & VR then:
Correct answer: C. VQ > VR
- A. EQ = ER
- B. EQ < ER
- C. VQ > VR
- D. VQ < VR
Explanation
The electric potential at a point is inversely related to the distance from a positive charge. Since Q is closer to the positive point charge P than R, VQ is greater than VR.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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