A point charges 0.4nC is located at (2,3,3). Find the potential differences between (2,3,3) m and (-2,3,3)m due to the charge:
Correct answer: C. 2.7
- A. 2.5
- B. 2.6
- C. 2.7
- D. 2.8
Explanation
Explanation is given below: For the second point (-2,3,3) meters, the distance (r2) is 4 meters. Now, let's calculate the potential difference: V2 = (8.988 x 10^9 Nm^2/C^2) x (0.4 x 10^-9 C) / 4 meters = 2.7 Volts The electric potential difference between the point charge at (2,3,3) meters and the point (-2,3,3) meters is exactly 2.7 Volts.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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