A point charges 0.4nC is located at (2,3,3). Find the potential differences between (2,3,3) m and (-2,3,3)m due to the charge:
Correct answer: C. 2.7
- A. 2.5
- B. 2.6
- C. 2.7
- D. 2.8
Explanation
Explanation is given below: For the second point (-2,3,3) meters, the distance (r2) is 4 meters. Now, let's calculate the potential difference: V2 = (8.988 x 10^9 Nm^2/C^2) x (0.4 x 10^-9 C) / 4 meters = 2.7 Volts The electric potential difference between the point charge at (2,3,3) meters and the point (-2,3,3) meters is exactly 2.7 Volts.
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