A point charge q is placed at a distance r from the center of an uncharged conducting sphere of radius R (R << r). The potential at any point on the sphere is:
Correct answer: B. V= k (q/r)
- A. Zero
- B. V= k (q/r)
- C. V=k qR2/r
- D. V=k qr/R2
Explanation
When a point charge q is placed at a distance r from the center of an uncharged conducting sphere of radius R (where R < r), the potential at any point on the sphere will be constant and equal to the potential due to the point charge q.The conducting sphere, bring uncharged, initially has an electric potential of zero everywhere on its surface. However, when the charged particle q is brought near the sphere, it induces an opposite charge distribution on the inner surface of the conducting sphere due to electrostatic induction. This induced charge distribution creates an electric field inside the sphere, which cancels out the electric field due to the point charge q at any point inside the conducting sphere.As a result, the electric potential on the inner surface of the conducting sphere becomes constant and equal to the potential due to the point charge q at a distance r from the center of the sphere. The electric potential on the inner surface of the sphere is given by the formula for the electric potential of a point charge:V = k * (q / r) Where:V is the electric potential,k is Coulomb's constant (approximately 8.99 x 10^9 N m^2/C^2),q is the charge of the point charge (in this case, it is q),r is the distance from the point charge to the point on the conducting sphere where the potential is measured.Therefore, the potential at any point on the sphere is given by V = k * (q / r). This potential is constant and equal to the potential due to the point charge q at a distance r from the center of the sphere.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Electrostatics
Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
Practise Electrostatics
831 free Electrostatics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Electrostatics questions
A capacitor stores 10µC charge when connected across a battery. When the gap between the plates is filled with a dielectric, a charge of 20µC flows through the battery. Find the dielectric constant of the dielectric.
What is the mechanical work done in pulling the slab out of the capacitor after disconnecting it from the battery:
An electric dipole has the magnitude of its charge as q and its dipole moment is p. It is placed in a uniform electric field E. If its dipole moment is along the direction of the field, the force on it and its potential energy are respectively :
Three charges are placed at the vertices of an equilateral triangle of sides 'a'. The force experienced by the charge placed at the vertex A in a direction normal to BC is :
Two identical capacitors have the same capacitance C. One of them is charged to potential V1 and the other to V2. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is:
An assembly of charges, +q, -q, +q, -q ........ are placed at distance x = 1m, x = 2m, x = 4m, x = 8m and so on, from the origin, in a plane. The potential at x = 0, due to the charges would be: