A pipe open at both ends has a length of 5m. The second harmonic frequency is _. The velocity of sound in air = 340 m/s.
Correct answer: C. 68 Hz
- A. 17 Hz
- B. 34 Hz
- C. 68 Hz
- D. 306 Hz
Explanation
Wavelength is the distance between consecutive nodes and antinodes. For the case of the second harmonic the distance between alternated nodes i.e. wavelength = the length of the tube. So, wavelength = 5m. Refer to the diagram below.Applying the formula for frequency;v=fλ340=f(5)f=340/5f=68 Hz
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Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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