A pipe open at both ends has a length of 5m. The second harmonic frequency is _. Velocity of sound in air = 340 m/s.
Correct answer: C. 68 Hz
- A. 17 Hz
- B. 34 Hz
- C. 68 Hz
- D. 306 Hz
Explanation
In the second harmonic frequency of the sound in an open tube, the wavelength is 1 lambda (as shown in the figure below; the distance of between two antinodes). Thus the length of tube= length of the wave (wavelength), i.e 5 m in our case.Applying the formula for frequency:v=fλ340=f(5)f=340/5f=68 Hz
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About Waves
Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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