A pipe of I.D. 4 m is bifurcated into two pipes of I.D. 2 m each. If the average velocity of water flowing through the main pipe is 5 m/sec, the average velocity through the bifurcated pipes is__________________?
Correct answer: D. 10 m/sec
- A. 20 m/sec
- B. 5 m/sec
- C. 5 √2 m/sec
- D. 10 m/sec
Explanation
The main-pipe area is 16π, while the combined area of two 2 m pipes is 2 × 4π = 8π. Continuity gives V_branch = (16π/8π) × 5 = 10 m/s.
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