A person carries a load of 15 kg of bricks to the top of building 10 m high. The work done is: (g = 10 m/s²)
Correct answer: C. 1500 J
- A. 150 J
- B. 100 J
- C. 1500 J
- D. 750 J
Explanation
We know that, W=PE=mghP.E = mghP.E = (15)(10)(10) = 1500 J
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About Work
Work is done when a force produces displacement, with its value determined by the component of force along the displacement. The topic covers positive, negative and zero work, work by variable forces from force-displacement graphs, and the connection between net work and change in kinetic energy.
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