A particle performs uniform circular motion with angular momentum 'L'. If the frequency of the particle's motion is halved and its KE is doubled then the angular momentum becomes:
Correct answer: B. 4L
- A. L/4
- B. 4L
- C. 2L
- D. L/2
Explanation
For a rotating particle KE = ½ I ω² and L = I ω, so L = 2K/ω. If K → 2K and ω → ω/2 then L(new) = 2(2K)/(ω/2) = 4·(2K/ω)/2 = 4 L. Thus the angular momentum becomes four times the original.
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Rotational motion relates angular displacement, angular velocity and angular acceleration to linear displacement, tangential velocity and tangential acceleration through the radius. Questions use radians, v equals r omega and tangential acceleration, while distinguishing tangential velocity from centripetal acceleration and angular quantities from their linear counterparts.
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