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A particle performs simple harmonic motion of amplitude 0.020 m and frequency 2.5Hz. What is its max speed?

Correct answer: D. 0.314 m/s

  • A. 0.008m/s
  • B. 0.050 m/s
  • C. 0.125 m/s
  • D. 0.314 m/s

Explanation

In simple harmonic motion (SHM), the maximum speed (Vmax) of a particle is related to its amplitude (A) and angular frequency (ω) by the formula:Vmax =A⋅ω.The angular frequency (ω) is related to the frequency (f) by the equation:ω=2πf.Calculating this expression gives the maximum speed (Vmax ).Vmax ≈0.314m/s

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About Simple Harmonic Motion

Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.

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