A particle of mass "m1" is moving with a velocity "v1" and another particle of mass "m2" is moving with a velocity "v2". Both of them have the same momentum but their different kinetic energies are "E1" and "E2" respectively. If m1 > m2 then:

Explanation

Given that: Particle 1: Mass = m1, Velocity = v1 ,Momentum = m1v1 ,Kinetic Energy = (1/2)m1v1^2 Particle 2: Mass = m2, Velocity = v2 ,Momentum = m2v2 = m1v1 (since both particles have the same momentum) Kinetic Energy = (1/2)m2v2^2We are given that both particles have the same momentum. We are asked to find the relationship between E1 and E2. Since the momentum of both particles is the same, we can write the following equation: m1v1 = m2v2=pSince the kinetic energy of a particle is equal to (1/2)mv^2=(1/2)p2/m, we can write the following equations for the kinetic energies of particle 1 and particle 2: E1= (1/2)p2/m1 E2=(1/2)p2/m2 dividing E2 by E1 E2/E1=m1/m2 E2=E1(m1/m2) As m1 > m2 so m1/m2 is greater than one so E1 will be greater than E2 Since m1 > m2, we know that E1 < E2. Therefore, the kinetic energy of particle 1 is less than the kinetic energy of particle 2.