A particle of mass 'm' is projected from the ground with an initial speed uo at an angle 'a' with the horizontal. At the highest point of its trajectory, it makes a completely in inelastic collision with another particle of mass which was thrown vertically upward from the ground with the same initial speed uo. The angle that the composite system makes with the horizontal immediately after the collision is?
Correct answer: A. 45°
- A. 45°
- B. 45°-a
- C. 45°+a
- D. 90°
Explanation
Tan θ = momentum of first collision/ momentum of second collision= 1 Tan 1 = 45°
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About Collisions
Collisions involve the conservation of linear momentum when bodies interact for a short time. The topic covers impulse, elastic and inelastic collisions, kinetic energy changes, and the coefficient of restitution, with calculations usually based on one dimensional motion. Momentum remains conserved in isolated collisions, but kinetic energy is conserved only in elastic collisions.
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A particle of mass 'm' is projected from the ground with an initial speed u0 at an angle 'α' with the horizontal. At the highest point of its trajectory, it makes a completely in-elastic collision with another particle of mass 'm' which was thrown vertically upward from the ground with the same initial speed u0. The angle that the composite system makes with the horizontal immediately after the collision is?
A particle of mass 'm' is projected from the ground with an initial speed u0 at an angle 'a' with the horizontal. At the highest point of its trajectory, it makes a completely inelastic collision with another particle of mass which was thrown vertically upward from the ground with the same initial speed u0. The angle that the composite system makes with the horizontal immediately after the collision is _.
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