A particle of mass m=9 x 10^-31 kg moving towards the wall of a vessel at a velocity of v=600 ms-1 strikes it at an angle of 60° to the normal and rebounds at the same angle at the same speed. The impulse of the force experienced by the wall during the impact is:
Correct answer: C. 5.4 x 10^-28 Ns
- A. 3 x 10^21 N s
- B. 9 x 10^-28 N s
- C. 5.4 x 10^-28 Ns
- D. 5.4 x 10^-27 N s
Explanation
Impulse = Change in momentum. The initial momentum mv cf the electron can be resolved into two components. (i) mv cos θ along + ve x-axis (ii) mv sin θ along - ve y-axis After rebounding from the wall, the momentum mv can again be resolved into two components. (i) mv cos θ along -.ve x-axis (ii) mv sin θ along - v y.axis There is no change in momentum along y-axis but there is a change in momentum along x-axis
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