A particle of mass 100g starts its motion from rest along a circular path of radius 10 cm. If its velocity becomes 10 ms-1 then its centripetal force is:
Correct answer: D. 100N
- A. 0.1 N
- B. 1 N
- C. 10 N
- D. 100N
Explanation
The centripetal force acting on the particle is 1 N. The formula for centripetal force is F = mv2/r, where F represents the centripetal force, m represents the mass of the particle, v represents the velocity of the particle, and r represents the radius of the circular path. Plugging in the values for m, v, and r in the formula, we get F = 100 N. F = mv²/r = (0.1)(10)²/0.1 = 100 N
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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