A particle in SHM has an amplitude of 0.12 m and a maximum speed of 0.6 m/s. What is its angular frequency?
Correct answer: B. 5 rad/s
- A. 3 rad/s
- B. 5 rad/s
- C. 6 rad/s
- D. 8 rad/s
Explanation
The maximum speed vmax in SHM is given by vmax = Aω. Thus, ω = vmax/A = 0.6 / 0.12 = 5 rad/s.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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