A particle carrying a charge 3e accelerates through a potential difference of 2V. The energy acquired by it is:
Correct answer: A. 6 eV
- A. 6 eV
- B. 1.5 eV
- C. 0.66 eV
- D. 12 eV
Explanation
Option A is correct since electric potential (V) is defined as the potential energy per unit charge(q).Potential energy= Vq3e x 2v = 6eV
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About Electrostatics
Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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