A particle carrying a charge 3e, accelerates through a potential difference of 2V. The energy acquired by it is?
Correct answer: B. 9.6 x 10^-19 J
- A. 1.6 x 10^-19 J
- B. 9.6 x 10^-19 J
- C. 9.6 x 10^-18 J
- D. 1.6 x 10^-18 J
Explanation
q = 3eq = 3 (1.6 х 10-19)V = 2V E = qV E = (3 х 1.6 x 10-19)(2V) E = 9.6 x 10-19 JThis is numerical so it can only have one answer so option B is correct.
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