A normal-visioned man whose father was colour-blind marries a woman whose father was also colour-blind. They have their first child as a daughter. What are the chances that this child would be colour-blind?
Correct answer: B. Zero percent
- A. 100%
- B. Zero percent
- C. 25%
- D. 50%
Explanation
Color blindness is an X-linked disease. So, a woman whose father was color blind will be a carrier for the disease. Color blindness is an X-linked disease. So, a woman whose father was color blind will be a carrier for the disease. After looking at the crosses, the daughter born to them can be either normal or a carrier for the disease, but the possibility of color blindness is zero percent. possibility of color blindness is zero percent. Color blindness is an X-linked disease. So, a woman whose father was color blind will be a carrier of the disease. After looking at the crosses, the daughter born to them can be either normal or a carrier for the disease, but the possibility of color blindness is zero percent. So, the correct option is 'Zero percent'.
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Mendel's laws explain segregation, independent assortment and the prediction of genetic ratios using alleles, genotypes and phenotypes. The chapter also covers linked genes, recombination and crossing over during meiosis, then applies pedigree reasoning to X-linked recessive traits, which show different inheritance patterns in males and females.
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