A neutron travels a distance of 24 m in a time interval of 3.6 x 10^-4 s. Assuming its speed was constant, find its kinetic energy. Take 1.7 x 10^-27 kg as the mass of the neutron:
Correct answer: A. 37.702 x 10^-19 joule
- A. 37.702 x 10^-19 joule
- B. 27.702 x 10^-19 joule
- C. 17.70 x 10^-19 joule
- D. 07.702 x 10^-29 joule
Explanation
The following is the solution:speed of neutron = distance travelled by neutron / time taken by neutron for covered that distance .speed of neutron = 24/3.6 × 10‐4 m/sspeed of neutron ( V)= 6.6 × 10⁴ m/sno ,kinetic energy = 1/2mv²K.E = 1/2 × 1.7 × 10-27 ×( 6.6 × 10⁴)² J= 1/2 × 1.7 × (6.6)² × 10-19 j=37.2 × 10-19 jso,K.E = 37.2 × 10-19.Hence the correct answer is A which is closest to the correct answer
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