Asked in MDCAT Test Series 14 — Work and Energy

A neutron travels a distance of 24 m in a time interval of 3.6 x 10^-4 s. Assuming its speed was constant, find its kinetic energy. Take 1.7 x 10^-27 kg as the mass of the neutron:

Correct answer: A. 37.2 x 10^-19 joule

  • A. 37.2 x 10^-19 joule
  • B. 27.702 x 10^-19 joule
  • C. 17.70 x 10^-19 joule
  • D. 7.702 x 10^-29 joule

Explanation

The following is the solution:speed of neutron = distance travelled by neutron / time taken by neutron for covered that distance .speed of neutron = 24/3.6 × 10‐4 m/sspeed of neutron ( V)= 6.6 × 10⁴ m/sno ,kinetic energy = 1/2mv²K.E = 1/2 × 1.7 × 10-27 ×( 6.6 × 10⁴)² J= 1/2 × 1.7 × (6.6)² × 10-19 j=37.2 × 10-19 jso,K.E = 37.2 × 10-19.Hence the correct answer is A which is closest to the correct answer

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About Work and Energy

Work transfers energy when a force causes displacement, while kinetic energy, gravitational potential energy and power describe motion, position and the rate of energy transfer. The work-energy theorem links net work with change in kinetic energy, and efficiency accounts for energy losses rather than treating them as energy destruction.

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