A motor car can be stopped within a distance of S, when it moves with a speed v. If it moves with a speed 4v, it can be stopped within a distance (assuming constant breaking force)
Correct answer: D. 16S
- A. S
- B. 4S
- C. 2S
- D. 16S
Explanation
The stopping distance is proportional to the square of the speed of the vehicle. This relationship is given by the formula S = k*v2, where S is the stopping distance, v is the speed, and k is a constant that depends on the braking force and other factors. When the speed is increased from v to 4v, the stopping distance becomes (4v)2 = 16v2. Therefore, the stopping distance is 16S. The other options do not correctly apply this squared relationship and are therefore incorrect.
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