A metal sulfate contains 9.87% of M. This sulfate is isomorphous with ZnSO4,.7H2O. Determine the atomic weight of the metal M.
Correct answer: A. 24.31
- A. 24.31
- B. 34.31
- C. 25.25
- D. 44.41
- E. 30.75
Explanation
To determine the atomic weight of the metal M, first recognize that the sulfate compound is isomorphous with ZnSO4.7H2O, meaning it has a similar structure, MSO4.7H2O. The molecular mass of MSO4.7H2O can be expressed as x + 32 (S) + 64 (4O) + 126 (7H2O) = 222 + x.Given that the metal M constitutes 9.87% of the total mass, set up the equation: (9.87/100) * (222 + x) = x. Solving this yields x = 24.31, indicating that the metal is magnesium.Other options do not satisfy this equation and percentage relationship, leading them to be incorrect.
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