A metal rod of length 30cm is moving at a speed of 0.5ms-1 in a direction perpendicular to a 0.25T magnetic field. Find the emf produced in the rod.
Correct answer: C. 3.75 x 10^-2V
- A. 3.13 x 10^-2V
- B. 4.13 x 10^-2V
- C. 3.75 x 10^-2V
- D. 4.75 x 10^-2V
Explanation
Explanation is given below: Using formula E= VBL V= 0.5 B= 0.25 L= 30cm converting to meters = 30/100= 0.3m 0.5×0.25×0.3 = 3.75×10-2 V
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About Electromagnetism
Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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