A metal rod of length 25 cm is moving at a speed of 0.5 m/s in a direction perpendicular to a 0.25 T magnetic field. Find the e.m.f produced in the rod.
Correct answer: D. 3.13 x 10^-2 V
- A. 6.9 x 10^-2 V
- B. 5.7 x 10^-2 V
- C. 4.6 x 10^-2 V
- D. 3.13 x 10^-2 V
- E. 2.3 x 10^-2 V
Explanation
The formula for emf is E=velocity x length of rod x magnetic field intensity The length of rod is 25 cm so first it must be converted into meters. =25x10-2 E= 0.5 x 0.25 x25 x10-2 = 3.13 x 10-2V
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Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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