A metal rod of length 10.0 cm is moving at a speed of 0.5 ms-1 in a direction perpendicular to a 0.20 T magnetic field. Find the emf produced in the rod.
Correct answer: C. 1.0 x 10^-2 V
- A. 2.0 x 10^-3 V
- B. 0.50 x 10^-2 V
- C. 1.0 x 10^-2 V
- D. 1.0 x 10^-3 V
Explanation
Motional emf = Bℓv (B,ℓ, and v perpendicular)Emf = (0.20T) * (0.1m) * (0.5m/s) = 0.01 = 1 * 10-2 V
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About Electromagnetism
Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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