Asked in MDCAT Test Series 26 — Electromagnetic InductionModerate

A metal rod of length 1 m is moving at a speed of 1m/s in the direction making to an angle of 30o with 0.5 T magnetic field. The emf produced is:

Correct answer: A. 0.25V

  • A. 0.25V
  • B. 2.5V
  • C. 0.025V
  • D. 25V

Explanation

The induced EMF (E) in a moving conductor within a magnetic field is calculated using the formula: E = B * l * v * sin(θ), where:B is the magnetic field strength (0.5 T)l is the length of the rod (1 m)v is the velocity of the rod (1 m/s)θ is the angle between the direction of velocity and the magnetic field (30o)Substituting these values, we have:E = 0.5 * 1 * 1 * sin(30o) = 0.5 * 1 * 1 * 0.5 = 0.25VTherefore, the correct answer is 0.25V. The other options result from errors such as incorrect application of the formula or miscalculation of the angle effect.

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About Electromagnetic Induction

Changing magnetic flux induces an emf according to Faraday's law, while Lenz's law gives the direction that opposes the change producing it. Transformers apply induction between coils to step alternating voltage up or down, with turns ratio, current transformation and energy losses determining practical operation.

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