A metal plate of thickness half the separation between the capacitor plates ofcapacitance C is inserted the new capacitance is
Correct answer: D. 2C
- A. C
- B. C/2
- C. 0
- D. 2C
Explanation
When a metal plate of thickness half the separation between the capacitor plates is inserted between the plates, the new capacitance can be found using the formula: C= k. ε0. A/dk is the relative permittivity (dielectric constant) of the material between the platesε0 is the vacuum permittivity.A is the area of the plates.d is the separation between the plates.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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