A material whose K absorption edge is 0.15 Å is irradiated with 0.1 Å X-rays. The maximum kinetic energy of the photoelectrons emitted from the K-shell is:
Correct answer: A. 41 keV
- A. 41 keV
- B. 51 keV
- C. 61 keV
- D. 71 keV
Explanation
Photon energy for 0.1 Å X-rays = 124 keV , while K-edge energy (0.15 Å) = 82. 7 keV .Photoelectron kinetic energy = incident photon energy - binding energy =124 - 82.7 = 41 keV.Hence , the maximum kinetic energy is 41 keV .
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Classical physics cannot explain blackbody radiation and related observations, leading to Planck’s quantum theory, in which energy is emitted or absorbed in discrete packets. Photons provide the particle model of light, with energy and momentum linked to frequency and wavelength, including the photoelectric effect and its threshold frequency.
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