A man whose weight is 900 N on the earth's surface goes to a height, which is equal to twice the earth's radius, above the surface of the earth, then the new weight of the man will be:
Correct answer: B. 225 N
- A. 900 N
- B. 225 N
- C. 300 N
- D. 100 N
Explanation
The following is the solution:Weight of object on earth W=GMm/r2Now, M=ρV =4πρR3/3∴W=GρπR3Gm/3R2=4πρRGm/3WP/WE=(ρP/ρE)(RP/RE)WP=900/12=75N
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