A man walk for some time with velocity v due east. Then he walks for same time with velocity v due north. The average velocity for man is:
Correct answer: D. v/√2
- A. 2v
- B. √2v
- C. v
- D. v/√2
Explanation
c) v/√2 This option suggests that the average velocity of the man is v. This is the correct answer. The average velocity of the man is equal to his total displacement divided by the total time taken. Since the man walks with velocity v due east and then with velocity v due north, his displacement is the diagonal distance between his initial and final positions, and the magnitude of this displacement is v. Dividing this displacement by the total time taken gives the average velocity, which is v/√2 .
This question appeared on the ETEA MDCAT 2017 paper, which you can sit online with every answer explained.
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About Displacement and Velocity
Displacement is the directed change in position, while velocity is the rate of change of displacement and includes both magnitude and direction. The topic connects position-time and velocity-time graphs with average and instantaneous values, and distinguishes displacement from distance and velocity from speed.
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