A man holds a bucket by applying force 10N. He then moves it a horizontal distance of 5m and a vertical distance of 10m, find out the net work done.
Correct answer: A. 100 J
- A. 100 J
- B. 150 J
- C. 50 J
- D. 200 J
Explanation
WD = f x d cos θ For horizontal distance let θ be 90˚ 10 x 10 x cos90 = 0 For vertical distance, θ is 0˚ 10 x 10 x cos0 = 100 Net work done = 100J
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About Work
Work is done when a force produces displacement, with its value determined by the component of force along the displacement. The topic covers positive, negative and zero work, work by variable forces from force-displacement graphs, and the connection between net work and change in kinetic energy.
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