A low energy neutron has RBE factor of 10. How much energy is absorbed by a man of mass 80 Kg. if the value of equivalent dose is 400 rem?
Correct answer: B. 32 J
- A. 16 J
- B. 32 J
- C. 48 J
- D. 64 J
Explanation
Explanation:Equivalent dose (rem) = RBE factor × Absorbed dose (rad) Absorbed dose (rad) = Equivalent dose (rem) / RBE factor = 400 rem / 10 = 40 rad.1 rad = 0.01 J/kg.Total absorbed energy (J) = Absorbed dose (rad) × Mass (kg) × 0.01 J/kg/rad = 40 rad × 80 kg × 0.01 J/kg/rad = 32 J.
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