A loop of radius 1 m is placed on an incline of 60 degrees with a magnetic field of 100 T, corresponding flux will be _.
Correct answer: C. 157 Wb
- A. 314 Wb
- B. 107 Wb
- C. 157 Wb
- D. 435 Wb
Explanation
Correct Option: CTo find the corresponding flux through the loop, we can use the formula:Flux (Φ) = B * A * cos(θ)Where:B is the magnetic field strength (100 T),A is the area of the loop,θ is the angle between the magnetic field and the normal to the loop.In this case, the loop has a radius of 1 m, so its area (A) is given by π * r^2:A = π * (1 m)^2 = π m^2The angle between the magnetic field and the normal to the loop is 60 degrees.Plugging these values into the formula, we get:Φ = (100 T) * (π m^2) * cos(60°)= (100 T) * (π m^2) * (1/2)= 50π T m^2To find the numerical value of the flux, we can use the approximate value of π as 3.14:Φ ≈ 50 * 3.14 T m^2≈ 157 T m^2
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About Electromagnetism
Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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