A long spring, when stretched by a distance x, has potential energy V. On increasing the stretching to nx, the potential energy of the spring will be:
Correct answer: C. n2 V
- A. nV
- B. V/n
- C. n2 V
- D. V/n2
Explanation
The potential energy stored in a spring that is stretched by a distance x is given by the formula: V = ½ kx² In this case, the potential energy of the spring when stretched by a distance x is given as V. When the stretching of the spring is increased to nx, the potential energy can be calculated by substituting nx for x in the formula: V' = ½ k (nx)² = ½ kn²x² = n² (½ kx²) V' = n²V
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