A light bulb draws 300 mA when the voltage across it is 240V. The resistance of the light bulb is:
Correct answer: C. 800 ohm
- A. 400 ohm
- B. 600 ohm
- C. 800 ohm
- D. 1000 ohm
Explanation
The measure of opposition applied by any object to the flow of electric current is known as resistance Resistance = Voltage / Current V= 240 V Current = 300 mA = 0.3 A R = 240/0.3 Resistance = 800 ohm Mathematically options A,B&D are incorrect
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Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.
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