A light bulb draws 300 mA when the voltage across it is 240V. The resistance of the light bulb is:
Correct answer: C. 800 ohm
- A. 400 ohm
- B. 600 ohm
- C. 800 ohm
- D. 1000 ohm
Explanation
The measure of opposition applied by any object to the flow of electric current is known as resistance Resistance = Voltage / Current V= 240 V Current = 300 mA = 0.3 A R = 240/0.3 Resistance = 800 ohm Mathematically options A,B&D are incorrect
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Current Electricity
Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.
Practise Current Electricity
1,052 free Current Electricity MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Current Electricity questions
A 250 V bulb passes a current of 0.3 A. Calculate the power in the lamp.
Resistance of a semiconductors decreases
PD stands for:
In order to achieve high accuracy, the slide wire of a potentiometer should be
An electric iron is 20V & 500W . The unit consumed by it (in kJ) in using it for 24 hours will be:
The circuit which gives continuously varying potential is called: