A light bulb draws 300 mA when the voltage across it is 240 V. The resistance of the light bulb is___________?
Correct answer: C. 800 Q
- A. 400 Q
- B. 600 Q
- C. 800 Q
- D. 1000 Q
Explanation
Using Ohm’s law, R=V/I=240/0.3=800 ohms. The 300 mA value must first be converted to 0.3 A.
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