A handball is tossed vertically upward with a velocity of 19.6 m/s. Approximately how high will it rise?
Correct answer: B. 19.6 m
- A. 15.8 m
- B. 19.6 m
- C. 25.6 m
- D. 30 m
Explanation
Initial velocity = 19.6 m/sEquation of motion = v = u - gtHeight h = ut - 1⁄2 gt2v = final velocity at max. height = 0g = acceleration due to gravity = 9.8 m/s2 t= time of motion. Hence we have,0 = 19.6 - 9.8tt = 2sh = 19.6 x 2 - 1/2 x 9.8 x 4h = 19.6 m
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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