A half-wave rectifier has an input voltage of 240 V r.m.s. If the step-down transformer has a turns ratio of 8:1, what is the peak load voltage? Ignore diode drop?
Correct answer: D. 42.5 V
- A. 27.5 V
- B. 86.5 V
- C. 30 V
- D. 42.5 V
Explanation
The transformer secondary voltage is 240/8 = 30 V rms, so its peak value is 30√2 ≈ 42.5 V. With the diode drop ignored, this is the peak load voltage.
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