A gas expands under constant pressure P from V1 to V2 . The work done by the gas is:
Correct answer: A. P(V2 −V1 )
- A. P(V2 −V1 )
- B. P(V1 −V2 )
- C. P(V1^γ −V2^γ )
- D. P(1/V1 −1/V2 )
Explanation
The work done by a gas under constant pressure P) during expansion or compression is given by P×(change in volume). Therefore, the correct expression is P(V2 −V1 ).
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About First Law of Thermodynamics
The first law relates heat supplied, work done and the change in internal energy through energy conservation. Problems use sign conventions and apply the law to isothermal, adiabatic, isobaric and isochoric processes. Internal energy is a state function, while heat and work depend on the path followed.
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