A galvanometer of resistance G is shunted by a very small resistance S. The resistance of the resulting ammeter is ______________?
Correct answer: A. GS/(G+S)
- A. GS/(G+S)
- B. G+S
- C. G-S
- D. None of the above
Explanation
The shunt S is connected in parallel with the galvanometer resistance G, so the equivalent resistance is the parallel combination GS/(G+S). The very small shunt resistance also allows the arrangement to carry larger current as an ammeter.
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