A force of F = 20 + 10y N is acting in y direction, work done by this force to move the particle from y= 0 to y = 1m?
Correct answer: D. 25 J
- A. 20 J
- B. 15 J
- C. 5 J
- D. 25 J
Explanation
The work done by the force F can be calculated using the formula W = ∫F.dy, where ∫F.dy represents the integral of the force F with respect to the displacement dy. In this case, the integral can be written as: W = ∫(20+10y)dy from y=0 to y=1 Evaluating this integral gives: W = [20y + 5y2] from y=0 to y=1 Substituting the limits of integration gives: W = [20(1) + 5(1)2] - [20(0) + 5(0)2] Simplifying this expression gives: W = 25 J Therefore, the work done by the force F to move the particle from y=0 to y=1 m is 25 J.
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About Work
Work is done when a force produces displacement, with its value determined by the component of force along the displacement. The topic covers positive, negative and zero work, work by variable forces from force-displacement graphs, and the connection between net work and change in kinetic energy.
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