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Asked in PMC Practice Test 30 (2021) 2021Moderate

A force of F = 1 + y N is acting in y direction, work done by this force to move the particle from y= 0 to y= 1m would be -------

Correct answer: C. 2 J

  • A. 0.5 J
  • B. 1 J
  • C. 2 J
  • D. 1.5 J

Explanation

To calculate the work done by a force, we can use the formula: Work = Force × Displacement × cos(θ) In this case, the force is given by F = (1 + y) N, and the displacement is from y = 0 to y = 1m. The angle θ is not specified, but assuming the force is acting directly in the y-direction, the angle between the force and displacement would be 0 degrees, and cos(0) = 1. Substituting the values into the formula: Work = (1 + y) × (1 - 0) × cos(0) = (1 + 1) × 1 × 1 = 2 J Therefore, the work done by this force to move the particle from y = 0 to y = 1m is 2 J

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About Work

Work is done when a force produces displacement, with its value determined by the component of force along the displacement. The topic covers positive, negative and zero work, work by variable forces from force-displacement graphs, and the connection between net work and change in kinetic energy.

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