A force of F = (1+y) N is acting in y direction. Work done by this force to move the particle from y = 0m to y = 1m is _.
Correct answer: D. 1.5 J
- A. 0.5 J
- B. 1 J
- C. 2 J
- D. 1.5 J
Explanation
When y = 0, F = 1 N. When y = 1, F = 2 N. Therefore the average value of F = (1 + 2)/2 = 1.5 N. Therefore the average work done will be Favg x displacement = 1.5 x (1 - 0) = 1.5 J. Hence, Option D is correct.
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About Work
Work is done when a force produces displacement, with its value determined by the component of force along the displacement. The topic covers positive, negative and zero work, work by variable forces from force-displacement graphs, and the connection between net work and change in kinetic energy.
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