A force of 10N acts on a body of mass 20kg for 10 seconds. The change in its momentum is
Correct answer: B. 100kgm/s
- A. 50kgm/s
- B. 100kgm/s
- C. 300kgm/s
- D. 1000kgm/s
Explanation
Step 1: Acceleration calculation Applying Newton's second law ∑F=ma ⇒F=ma ⇒10(N)=20(kg) a ⇒a=0.5m/s2 Step 2: Final speed Since acceleration is constant, ∴ Applying equation of motion v=u+at u= Initial speed =0 v= Final speed v=0+0.5(m/s2)×10(s) =5m/s Step 3: Change in momentum ΔP ΔP=m(v−u) =20(5−0)kgm/s =100kgm/s Hence option B is correct. numerical type question so only one answer is possible
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