A force F acting on an object varies with distance x as shown in figure. The work done by the force in moving the object from x= 0 to x=6m is:
Correct answer: C. 13.5J
- A. 18J
- B. 9J
- C. 13.5J
- D. 4.5J
Explanation
W= area under the F-x graph; W= 1/2 (sum of parallel sides)(perpendicular distance between parallel sides) = 1/2 (6+3)(3)= 13.5J.
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About Work and Energy
Work transfers energy when a force causes displacement, while kinetic energy, gravitational potential energy and power describe motion, position and the rate of energy transfer. The work-energy theorem links net work with change in kinetic energy, and efficiency accounts for energy losses rather than treating them as energy destruction.
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